G great len5 for x Objective Knowledge Check Question 10 Ca

G great len5 for \" x Objective Knowledge Check Question 10 Calculate the energy required to heat 528.0 g of water from 27.4 to 33.7 °C. Assume the speonc heat capacity of water urder these conations is 418 1g K Round your answer to 2 signficant digts.

Solution

Ans. Amount of heat required by water during increase its temperature is given by-

q = m s dT                            - equation 1

Where,

q = heat required

m = mass of water

s₁ = specific heat of water

dT = Final temperature – Initial temperature = (T2 – T1)⁰C

            = 33.7⁰C – 27.4⁰C = 6.3⁰C = 6.3 K

Note that temperature difference in ⁰C units is same as in K units.

Putting the values in equation 1-

            q = 528.0 g x (4.18 J g^-1 K^-1) x 6.3 K

Hence, q = = 13904.352 J

Therefore, total heat released = 1.4 x 10⁴ J (2 significant figures)