G A Solutio W weebly 0 Summer X Smartwo Smartwo 40699

× \\ G A Solutio × . \\ W weebly. × \\0 Summer X Smartwo. × Smartwo /40699 94% This is a Numeric Entry question/itis worth 3 points/You have unlimited attempts/There is no attempt penalty a See page 576 03 Question (3 points) How many moles of solute are there in the following solutions? v 12th attempt A: See Periodic Table 8 See Hint Part 1 (1 point) mol 1.35 101 mglucose solution made by dissolving the glucose in 100.0kg of water: Part 2 (1 point) mol 2.50-10 mNa,CrOs solution made by dissolving the Na,CrO, in 10000 g of water: 002s Part 3 (1 point) 1.80x10, murea solution made by dissolving the urea in 5000gofwater: 0900 mol 11th attempt See Periodic Table QSee Hin Part 1 (1 point) Feedback mol 1.35x101 mglucose solution made by dissolving the glucose in 1000kg of water:0140 K 0312 VIEW SOLUTION 11 OF 12QUESTIONS COMPLETED

Solution

Part 1

molarity of glucose = 1.35 x 10^-1 molar = 0.135 molar

density of water is 1 that mean 1 killogram water = 1 liter water

1000 killogram water = 1000 liter water

thus volume of solution = 1000 liter

use following formula to find number of moles from molarity and volume

no of moles = molarity x volume in liter

substitute values in above equation

no of moles of glucose = 0.135 x 1000 = 135

Number of moles of glucose = 135 moles

Part 2

molarity of Na₂CrO₄ = 2.5 x 10^-2 molar = 0.025 molar

density of water is 1 that mean 1 gram water = 1 ml water

therefore 1000 gram water = 1000 ml water = 1 liter water

formula to find number of moles from molarity and volume is given bellow

number of moles = molarity x volume in liter

substitute values in above equation to find no of moles of Na₂CrO₄

no of moles of Na₂CrO₄ = 0.025 x 1 = 0.025 mole

no of moles of Na₂CrO₄ = 0.025 mole

Part 3

molarity of urea = 1.8 x 10^-2 molar = 0.018 molar

density of water is 1 that mean 1 gram water = 1 ml water

therefore 500 gram water = 500 ml water = 0.5 liter water

formula to find number of moles from molarity and volume is given bellow

number of moles = molarity x volume in liter

substitute values in above equation to find no of moles of urea

no of moles of urea = 0.018 x 0.5 = 0.009 mole

no of moles of urea = 0.009 m0le