Find all real numbers in the interval 0 2pi that satisfy the

Find all real numbers in the interval [0, 2pi) that satisfy the equation. Round approximate answers to the nearest tenth sin 2x - sin x cos x = sin x The solution set is {}. (Simplify your answer. Use integers or fractions for any numbers in the expression. Type an exact answer, using pi as needed. Use a comma to separate needed.

Solution

Sin 2x-sinxcos x=sin x

2sin x cos x-sin x cos x -sin x=0

sin x cos x -sin x=0

Sin x(cos x -1)=0

Sin x=0 , cos x=1

x=0,pi