witives is 212 i42214 51 Need Help ESmitili li thirtiem inem
Solution
1)
center (h,k)=((4+4)/2,(2-2)/2)=(4,0)
vertices (h,k+b)=(4,2),(h,k-b)(4,-2)
foci (h,k+be)=(4,5),(h,k-be)=(4,-5)
b =2,be=5
be/b =5/2
e=5/2
e=(1+(a/b)2)
(1+(a/2)2)=5/2
(1+(a/2)2)=25/4
(a/2)2=21/4
a2=21
a=21
equation of hyperbola is of form -(x-h)2/a2+(y-k)2/b2=1
equation of hyperbola is -(x-4)2/21 +(y-0)2/4=1
equation of hyperbola is -((x-4)2/21)+(y2/4)=1
