When a child emptied his coin bank he and a collection of pe

When a child emptied his coin bank, he and a collection of pennies, nickels, and dimes. There were 20 more pennies than dimes and the number of nickels was triple the number of dimes. If the coins had a value of $5, 40, how many of each type coin were in the bank?

Solution

Let the child had \'p\', \'n\', \'d\' pennies, nickles and dimes respectively

given is

p = 20 + d

n = 3d

The dime is a US coin worth ten cents. Ten dimes make a dollar.

Nickel\'s Worth 5 cents

A penny is worth 1 cent

So,

Given total value is 5.40$

0.01p + 0.05n + 0.1d = 5.40

Putting these values in above

p = 20 + d

n = 3d

0.01 (20+d) + 0.05 (3d) +0.1d = 5.4

0.2 + 0.01d + 0.15d + 0.1d = 5.4

0.26d = 5.2

d =20

So, 20 dimes

n = 3d = 60 nickles

p = 20 +d = 40 pennies