A file size of eleven 11 Megabytes is transmitted from one c

A file size of eleven (11) Megabytes is transmitted from one computer to another computer on a local area network using Ethernet protocol (IEEE 802.3). The protocol converts the data to data frames using the frame structure shown below How many frames are needed to transmit the file? Note 1 MB = 1024 * 1024 bytes The answer is an integer number; like 1000, 3500, or 4891. The Frame Structure of IEEE 802.3 used for this problem

Solution

Total size of a IEEE 802.3 frame : 7 + 1 + 6 + 6 + 2 + 1468 + 4 = 1494 bytes

Total size in bytes of the file to be transmitted = 11 Megabytes = 11 x 1024 KB = 11 x 1024 x 1024 bytes

Frames needed to transfer file = (11 x 1024 x 1024) / 1468 = 7857.17 = 7858 (since frames are indivisible).

Total overhead in one frame is the total bytes in a frame that do not constituent data = 1494 - 1468 = 26 bytes

Thus, total overhead in transferring the file = 26 bytes * 7858 = 204308 bytes