Give an on algorithm to determine if there exists an integer
Solution
1. We can use the idea as how the Binary search works, this problem can be thought as to find an index i such that A[i] = i .So there will be no input as Key
 
 1. Find low and high using array. Find the mid.
 2. Check if mid is more than the array value then search in left. by making as high = mid -1
 3. Check if mid is less than the array value then search in right by making low as mid+1;
 4. Other wise return mid;
 
 If No such index found return -1;
 
 
 Algorithm Search(A)
 Start
 low = 1 , high = length(A)
    while low < high
    mid = (low + high)/ 2
 if A[mid] < mid //index is more so we have to search in left part as elements are even higher in right
    high =. mid - 1 ;
 else if A[mid] > mid //index is less so we have to search in right part as elements are even lower in left
    low =. mid + 1 ;
    else
    return mid;
 return -1
 
 end
      
Time Complexity is O(log n)
 
 
 ii). If we need a loose bound algorithm: O(N)
 
 Start from the index 0 till the length of array check if index i equal to array element. If Yes return the elment
 otherwise return -1
 
 Algorithm Search(A)
 Start
   for i in 1: length(A)
    if A[i] == i
    retun i
return -1;
 End
![Give an o(n) algorithm to determine if there exists an integer i such that -4[i] = i in an array A[1..n] of integers where A[1] Solution1. We can use the idea   Give an o(n) algorithm to determine if there exists an integer i such that -4[i] = i in an array A[1..n] of integers where A[1] Solution1. We can use the idea](/WebImages/39/give-an-on-algorithm-to-determine-if-there-exists-an-integer-1120311-1761596037-0.webp)
