A beaker with 110 A beaker with 110Solution5 476 log SA S

A beaker with 1.10
A beaker with 1.10

Solution

5 = 4.76 + log (S/A)

=> S/A = 1.738

S+A = 0.1

=> A = 0.0365 M

and S = 0.0635 M


pH = 4.76 + log (0.0635 x 0.11 - 0.0062 x 0.49 / 0.0365x0.11 + 0.0062 x 0.49)

=> pH = 4.508

Change = 5 - 4.508 = 0.492

 A beaker with 1.10 A beaker with 1.10Solution5 = 4.76 + log (S/A) => S/A = 1.738 S+A = 0.1 => A = 0.0365 M and S = 0.0635 M pH = 4.76 + log (0.0635 x 0.1

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