A beaker with 110 A beaker with 110Solution5 476 log SA S
 A beaker with 1.10
  A beaker with 1.10
Solution
5 = 4.76 + log (S/A)
=> S/A = 1.738
S+A = 0.1
=> A = 0.0365 M
and S = 0.0635 M
pH = 4.76 + log (0.0635 x 0.11 - 0.0062 x 0.49 / 0.0365x0.11 + 0.0062 x 0.49)
=> pH = 4.508
Change = 5 - 4.508 = 0.492

