Solve the triangle with a 139 c 10 and B 34 degreeSolutio

Solve the triangle with a = 13.9, c = 10, and B = 34 degree.

a = 13.9 , c = 10

B = 34 degrees

applying law of cosines

b^2 = a^2 + c^2 - 2 ac cos B

plugging the values we get

b^2 = 13.9^2 + 10^2 - 2(10)(13.9) cos 34

b = 7.92

applying law of sines

b/ sin B = a / sin A

7.92 / sin 34 = 13.9 / sin A

A = 79 ( round off to nearest degree)

b/ sin B = c/ sin C

7.92 / sin 34 = 10 / sin C

C = 67 degrees ( round off )