Find the equation of the tangent of the curve x y2 at the p

Solution

equation of the tangent of the curve x = y^2 at the point (1, 1).

y = sqrt(x)

dy/dx = m = slope = 1/2 sqrt(x)

at point (1,1) = slope = m = 1/2

eqaution of tangent:

y -1 = 1/2 (x-1)

2y-2 = x-1

2y = x+1