a Find a solution for theta sec 5theta 8 degree csc 4 thet

(a) Find a solution for theta: sec (5theta + 8 degree) = csc (4 theta+ 3 degree) (b) Find the reference angle for theta = 1411 degree

Solution

6)

a)

sec(5 +8^o)=csc(4 +3^o)

sec(5 +8^o)=sec(90^o-(4 +3^o))

sec(5 +8^o)=sec(87^o-4)

=>(5 +8^o)=(87^o-4)

=>5+4=87^o-8^o

=>9=79^o

=>=(79_/9)^o

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(b)

=1411^o

=1411^o-(3*360^o)

=331^o

reference angle for =360^o-331^o

reference angle for =29^o