Find the terminal point Px y on the unit circle determined b

Find the terminal point P(x, y) on the unit circle determined by the given value of t. t = -7 pi/4 P(x, y) = ()

Solution:

t = 7/4 = 3/2 + /4

that is ponit P(x,y) lie in 4th quadrant

therefore

here reference angle is /4

x = cos(/4) and

y = - sin(/4)

or x = 1/2

and y = - 1/2

therefore P(x,y) = (1/2 , - 1/2)

Answer