Please help with the second part of this problem the six spe

Please help with the second part of this problem, the six specific solutions:

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places where appropriate.) sin theta = - Squareroot 3/2 theta = 4 pi/3 + 2 pi k, 5 pi/3 + 2 pi k rad List six specific solutions. theta = _________ rad

Solution

We know that the sin(pi/3) = sqrt(3)/2.

If sin is negative, then:
sin(pi + pi/3) = sin(4pi/3) = -sqrt(3)/2
sin(2pi - pi/3) = sin(5pi/3) = -sqrt(3)/2

for 4 other solutions, just add or subtract 2pi.
solutions are: (4pi/3, 5pi/3, 10pi/3, 11pi/3, 16pi/3, 17pi/3)