Find the angle x in terms of two inverse trigonometric funct

Find the angle x in terms of two inverse trigonometric functions: What is sec (pi/2 - x)? Express the answer as a simple fraction.

sinx=opposite/hypotenuse=7/25

x=arcsin(7/25)=16.26

adjacent=sqrt(625-49)=24

cos x=24/25

x=arccos(24/25)=16.26°

sec(pi/2-x)=cscx=1/sin x=25/7

$Find the angle x in terms of two inverse trigonometric functions: What is sec (pi/2 - x)? Express the answer as a simple fraction.Solutionsinx=opposite/hypoten$

Find the angle x in terms of two inverse trigonometric funct

Solution

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