how many liters of gas is 108 grams of nitrogen at 780mmHg a

how many liters of gas is 10.8 grams of nitrogen at 780mmHg and 38 degrees C?

780 mHg = (780/760) x 1.01325 x 10^5 Pa

PV = m.R.T/M

M = molecular mass = 28 gm

R = 8314 J/Kg.K

so (780/760) x 1.01325 x 10^5 x V = 10.8 x 8314 x (273 + 38)/ 28

so Volume = V = 9.59 m^3 = 9590 lites