double x 12 double myNum 8 double otherNum 20 double sale
Solution
answer is 97
double x=12,myNum=8,otherNum=20;
 double sale[5]={34,56,60,12};
 otherNum+=sale[3]; //20+12=32
 sale[2]=myNum*10; //8*10=80
     for(int i=0;i<4;i++) //add all the elementsin the array sale to variable x
 x+=sale[i];
//after loop x is 194
 myNum=x/2; //194/2 =97
 cout<<myNum<<endl;
this code prints 97
![double x = 12; double myNum = 8; double otherNum = 20; double sale[5] = {34, 56, 60, 12}; otherNum += sale[3]; sale[2] = myNum * 10; for(int i = 0; iSolutionan  double x = 12; double myNum = 8; double otherNum = 20; double sale[5] = {34, 56, 60, 12}; otherNum += sale[3]; sale[2] = myNum * 10; for(int i = 0; iSolutionan](/WebImages/40/double-x-12-double-mynum-8-double-othernum-20-double-sale-1121446-1761596898-0.webp)
