Consider the non negative integer solutions for the equation
Solution
Solution (a)
x1+x2+x3+x4+x5=36
The solution is given as :
The number of ways of dividing \'n\' identical objects into \'r\' groups with each group getting non-negative number of objects is given by (n+r-1) C (r-1).
n= 36 and r=5
Distinct solutions = (36+5-1) C (5-1) = 40 C 4
Solution (b)
If x1 is fixed then the number of solutions for the other variables is = 36-x1+5 C 5
where x1 is greater than equal to 12 means x1 will vary from 12 to 36
total solutions are = 29 C 5 + 28 C 5 + 27 C 5 + 26 C 5 + 25 C 5 + 24 C 5 + 23 C 5 + 22 C 5 + 21 C 5 + ..... + 5 C 5
Solution (c)
If x1 is fixed then the number of solutions for the other variables is = 36-x1+5 C 5
where x1 is less than 18 means x1 will vary from 0 to 17
total solutions are = 41 C 5 + 40 C 5 + 39 C 5 + .......... + 24 C 5

