P2BKH A BGH ALA AB ABCH A BG AFG ABQ ABCX Solution1 Eliminat

P2=-BKH A BGH ALA AB ABCH A BG+ AFG+ ABQ ABCX

Solution

1.
Eliminating common terms,
Da = A\'BC\'X\' + AB\'C\'X\' + AB\'CX\' + ABC\'X\' + ABCX\'
= X\'.((A\'+A)BC\' + (C\'+C)AB\' + ABC)
= X\'.(1.BC + 1.AB\' + ABC)
=X\'.((1 + A)BC + AB\')
=X\'.(BC + AB\')
=BCX\' + AB\'X\'

2.
Eliminating common terms,
Db = A\'B\'CX\' + A\'BC\'X\' + A\'BCX\' + AB\'CX\' + ABC\'X\' + ABCX\'
=X\'.((A\' + A)B\'C + (A\' + A)BC\' + (A\' + A)BC)
=X\'.(1.B\'C + 1.BC\' + 1.BC)
=X\'.((B\' + B)C + BC\')
=X\'.(C + BC\')
=X\'.C
=CX\'

3.
Dc = A\'B\'C\'X\' + A\'B\'CX\' + A\'BC\'X\' + A\'BCX\' + AB\'C\'X\' + AB\'CX\' + ABC\'X + ABCX\'
=X\'.((C + C\')A\'B\' + (C + C\')A\'B + (C\' + C)AB\' + (C\' + C)AB)
=X\'.(A\'(B + B\') + A(B\' + B))
=X\'.(A\' + A)
=X\'