Using the equation below assume we want to use 23 g of Feno3

Using the equation below assume we want to use 2.3 g of Fe(no3)3 in our experiment. how much NaOH will be needed for a complete reaction? show work

Fe(NO3)3+3NaOH--> Fe(OH)3 + 3 NaNo3

The chemical equation shows that 3 moles NaOH consume 1 mole Fe(NO3)3.
Hence for 100% yield 2.3/241.86 = 0.0095 moles Fe(NO3)3 are consumed by 3 * 0.0095 = 0.285 moles NaOH.
So grams of NaOH = 0.285 * 39.997 = 1.141 g