Evaluate the limit if exists Use LHospitals Rule Lim x appro
Evaluate the limit (if exists). Use L\'Hospitals Rule.
Lim x approachs 0 (3 LN x)/ (5x^-1)
Lim x approachs 0 (3 LN x)/ (5x^-1)
Solution
Lim (3 ln x/ 5x^-1)
x-> 0
As x-> 0, the given function would tend to infinity /infinity, which is undefined
Using L\'Hospitals rule,
the given limit can be evaluated by differentiating both the numerator and the denominator
=> Lim ( 3/x / -5/x2)
x-> 0
= Lim (-3/5)*x
x-> 0
= 0
