Evaluate the limit if exists Use LHospitals Rule Lim x appro

Evaluate the limit (if exists). Use L\'Hospitals Rule.

Lim x approachs 0 (3 LN x)/ (5x^-1)

Solution

Lim (3 ln x/ 5x^-1)
x-> 0

As x-> 0, the given function would tend to infinity /infinity, which is undefined

Using L\'Hospitals rule,

the given limit can be evaluated by differentiating both the numerator and the denominator

=> Lim ( 3/x / -5/x2)

x-> 0

= Lim (-3/5)*x

x-> 0

= 0

Evaluate the limit (if exists). Use L\'Hospitals Rule. Lim x approachs 0 (3 LN x)/ (5x^-1)SolutionLim (3 ln x/ 5x^-1) x-> 0 As x-> 0, the given function w

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