TS AND TANGENTS ses 112 find the value of x 2 23 23 3 6 5 10

TS AND TANGENTS ses 1-12, find the value of x 2. 23 23 3. 6. 5. 10 9. 8. 1. 10 4x 12. 10. 12 x + 2 20

Solution

1) 23 * x = 23 * 15. Therefore x = 15

2) 6*x = 4*3. Therefore x = 2

3) 8*x = 6*16. Therefore x = 12

4) 3* (3+x) = 2 (10 + 2). Therefore 9 + 3x = 24. 3x = 15. Therefore x = 5

5) 4* (4+x) = 5 (3 + 5). Therefore 16 + 4x = 40. 4x = 24. Therefore x = 6

6) 5* (5+x) = 6 (6 + 4). Therefore 25 + 5x = 60. 5x = 35. Therefore x = 7

7) 5 * (5 + x) = 10 * 10. Therefore 25 + 5x = 100. 5x = 75. Therefore x = 15

8) 9 * (9 + 7) = x * x. Therefore x² = 144. x = 12.

9) 9 * (9 + 4x) = 15 * 15. Therefore 81 + 36x = 225. 36x = 144. Therefore x = 4

10) (x-2) * (x-2 + x +2) = x². Therefore x² = (x-2) (2x) .

x² = 2x² - 4x

4x = 2x² - x²

x² = 4x. Therefore x = 4

11) 6 * (x + 4) = x *12. Therefore 6x + 24 = 12x. 6x = 24. Therefore x = 4

12) 20 (20 + x) = 15 (15 + 3x)

400 + 20x = 225 + 45x

25x = 175. Therefore x = 7