A proton is projected with a velocity of 70 kms into a magne

A proton is projected with a velocity of 7.0 km/s into a magnetic field of 0.60 T perpendicular to the motion of the proton. What is the magnitude of the magnetic force that acts on the proton? (e = 1.60 times 10^-19C) 4.2 times 10^-16 N 3.4 times 10^16 N 6.7 times 10^-16N 0 N 13 times 10^16 N In the figure, which of the Phase diagrams represents a series RLC circuit driven at resonance? A 120-V rms voltage at 60 Hz is applied across an RC circuit. The rms value of the current in the circuit is 0.60 A, and it leads the voltage by 60degree. What is the resistance in this circuit? 120 ohm 200 ohm 150 ohm 100 ohm 60 ohm The energy density of an electromagnetic wave in free space is equally divided between the magnetic and the electric fields. entirely in the electric field. entirely in the magnetic field. 1/4 in the electric field and 3/4 in the magnetic field. 1/4 in the magnetic field and 3/4 in the electric field.

Solution

(13) F = q (B x v) = 1.6x10^-19 x 0.60 x 7.0 x 10^3 = 6.72 x 10^-16 N

So, option (C) is the correct answer.

(14) Option (C) is the correct answer.

Explanation:

At resonance, V(L) = V(C)

And the circuit is purely resistive.

(15) Here, w = 2*pi*f = 2*3.14*60 = 376.8

Now, impedence of the circuit, Z = 120/0.6 = 200 OHM = SQRT[X(C)^2 + R^2]

Again tan 60 = X(C) / R = 1.732

=> X(C) = 1.732*R

Putting this value in the above expression -

X(C)^2 + R^2 = 40000

=> 3R^2 + R^2 = 40000

=> R = 100 Ohm

Hence, option (D) is the correct answer.

(16) Option (A) is the correct answer.

Explanation:

For an electromagnetic wave in free space, half the energy is in the electric field and half is in the magnetic field.