how many liters of 40 alcohol solution must be mixed with 60

how many liters of 40% alcohol solution must be mixed with 60 liters of 70% solution to get 50% solution

Equation 1

for quantity

x + 60 = y

for alcohol

0.4*x + 0.7*60 = 0.5*y

Solving both equations:

x = 120 L

y = 180 L

Ans 120 L of 40$ alcohol must mixed with 60L of 70% solution to get 50% solution.