Shuffle one deck of Fraction Bars deal each player eight bar
Solution
a) to be played in person.
b) Though I can hardly make out the parts shaded in the picture you uploaded, however, if player A has played the fraction bar with 1/2 shaded portion, then the probable fraction bars for the player B to win can be (3/4), (7/12), (3/3) or (5/6), since all of these fractions are higher than (1/2).
To be playing with proper diligence, player B should choose the fraction which is the lowest , so that he still has left with the higher shaded fractions with him for the further chances of the game.
3/4= 0.75
7/12=0.583
3/3=1
5/6=0.833
Therefore, player B should lay down the fraction bar with 7/12, since it is the lowest among the bar which could make him win and he is still left with fraction bar with higher chances of winning.
c) If Player 2 has started the game, then he should not choose the zero bar to start the game because he should save it for those instances where he has no chance of winning. for example, if player 1 plays a bar with 3/3 or so, then player B has no chance of putting any bar,he should save it for instances like that so that he can make the player 1 waste his higher fractioned bar against his lowest zero bar.
Thats how the trick should go.

