Homework SourseIn a physics lab experiment a spring clamped to the table sh
In a physics lab experiment, a spring clamped to the table shoots a 22 g ball horizontally. When the spring is compressed 22 cm , the ball travels horizontally 4.9 m and lands on the floor 1.4 m below the point at which it left the spring.
What is the spring constant?
In a physics lab experiment, a spring clamped to the table shoots a 22 g ball horizontally. When the spring is compressed 22 cm , the ball travels horizontally 4.9 m and lands on the floor 1.4 m below the point at which it left the spring.
What is the spring constant?
What is the spring constant?
Solution
PE of the spring = KE of the block
0.5kx^2= 0.5mv^2
v = x*sqrt(k/m)
v = 0.22 * sqrt(k/0.022)
v = 1.4832 sqrt k
x = Ux*t
y = uyt - 0.5gt^2
t = x/Ux = 4.9/1.4832 sqrt k
t = 3.3 / sqrt k - --------(1)
1.4 = 0.5*9.8*(3.3/sqrt k)^2
k = 38.2 N/m
