A student ran the follaboratory at 294 When she introduced 7

A student ran the follaboratory at 294 When she introduced 7.22x102 moles of CH2Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of CH2CI2(g) to be 5.55x10 M Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc Submit Answer Retry Entire Group 3 more group attempts remaining

Solution

        2CH2Cl2(g) <----> CH4(g) + CCL4(g)

initial   0.0722 M          0        0

change    -0.0666

equil      0.00555        +0.0333    +0.0333

Kc = [CCl4][CH4]/[CH2Cl2]

Kc = (0.0333*0.0333)/0.00555

     = 0.2