please help explain how to solve this system 2a3bx a2by the

please help explain how to solve this system: 2a+3b=x. -a+2b=y.

the answer is a=2x-3y/7. and b= a+2y/7 but I forgot the steps. please show in detail. thanks!

Solution

2a + 3b = x

-a + 2b = y

Now multiply 2nd eq. with 2

2a + 3b = x

-2a + 4b = 2y

Now add both equation

2a + 3b + (-2a + 4b) = x + 2y

7b = x + 2y

b = (x + 2y)/7

Now use above equation to solve for a

2a + 3(x + 2y)/7 = x

2a = x - 3x/7 - 6y/7

2a = (4x - 6y)/7

a = (2x - 3y)/7

Comment below if you have doubt in any steps.

please help explain how to solve this system: 2a+3b=x. -a+2b=y. the answer is a=2x-3y/7. and b= a+2y/7 but I forgot the steps. please show in detail. thanks! So

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