FOR ADDRESS BLOCK AND SUBNET SIZES Detail Examination of Ad

FOR ADDRESS BLOCK AND SUBNET SIZES ( Detail Examination of Addressing in the Internet Protocol)

172.26.12.0/22          

SIZE OF SUBNET 1 = 90      

SIZE OF SUBNET 2 = 2

SIZE OF SUBNET 3 = 20

Determine the Internet addresses that describe each of the 3 subnets using FLSM

Determine the Internet addresses that describe each of the 3 subnets using VLSM.

Present the following information for each one of the 3 assigned subnets in the two scenarios (6 in total):

Network address

First usable address of the subnet

Last usable address of the subnet

Broadcast address for the subnet

Prefix length

Subnet mask

Present in the following table format

Subnet #      Prefix Length        Subnet Mask               # Required Hosts              Max # of Hosts           First Address       Last Address        Broadcast Address

Solution

The IP address 172.26.12.0/22 belongs to the Class B ,

By using FLSM,

First Address :

172.26.12.1

Last Address :   172.26.12.2

Broadcast Address:

172.26.12.3

By using VLSM:

a) Network Address : 172.26.12.0

Subnet size : 90

Allocated size : 126

Subnet mask : /25

Range : 172.26.12.1 - 172.26.12.126

Broadcast address : 172.26.12.127

b) Network Address : 172.26.12.128

Subnet size : 20

Allocated size : 30

Subnet mask : /27

Range : 172.26.12.129 - 172.26.12.158

Broadcast address : 172.26.12.159

c) Network Address : 172.26.12.160

Subnet size : 2

Allocated size : 2

Subnet mask : /30

Range : 172.26.12.161 - 172.26.12.162

Broadcast address : 172.26.12.163