A container of toluene spilled in a closed room The contents

A container of toluene spilled in a closed room. The contents completely evaporated and produced a concentration of 90 ppm. How many liters were lost in the chemical spill? Considering that the room volume was 5000 cubic meters. The specific gravity of toluene is 0.86.

Solution

Ans

The concertration of tolune=90ppm = 90g/ m³= (90/1000) Kg/m³

This tolune is spread all over the room.

Mass of tolune = 5000m³ X (90/1000) Kg/m³ = 450 Kg

Sp gravity of tolune=0.86

Hence the density of tolune (at 250C) = 0.86 X density of water at that temp=0.86 X997 Kg/m3=857 Kg/m³

So the volume of tolune= mass /density = 450 kg/ (857 Kg/m³)=0.5248303 m³=524.83 L

(Rounded up to 2 significant figures)