Find the area of triangle ABC with the given parts a 42 ft

Find the area of triangle ABC with the given parts. a = 42 ft b = 54 ft c = 66 ft A) 126 ft^2 B) 1414 ft^2 C) 1697 ft^2 D) 1131 ft^2 A = 36.8 degree b = 11.8 in c = 8.5 in A = 30 in^2 B) 42 in^2 C) 28 in^2 D) 40 in^2 Solve the triangle, if possible, by finding the missing parts. a = 8.3 in. b = 13.8 in c = 15.1 in A) A = 30.99 degree, B = 64.86 degree, C = 84.15 degree B) No triangle satisfies the given conditions. C) A = 32.99 degree, B = 64.86 degree, C = 82.15 degree D) A = 34.99 degree, B = 62.86 degree, C = 82.15 degree Solve the triangle, if possible, by finding the missing parts. B = 42.2 degree C = 108.7 degree b = 34.48 A) = 27 1 degree, a = 48.62 c = 24.96 B) A = 29.1 degree, a = 26.96, c = 50.62 C) A = 29.1 degree, a = 24.96, c = 48.62 D) A = 27.1 degree, a = 50.62, c =26.96 Find the missing parts of the triangle. B = 21.0 degree b = 2.04 a = 19.7 A) No solution B) A = 9.5 degree, C = 148.5 degree, c = 23.74 c) A = 11.5 degree, C = 148.5 degree, c = 25.74 D) A = 10.5 degree, C = 148.5 degree, c = 21.74 A) B = 60 degree, C = 90 degree, b = 5 B) B = 90 degree, C = 60 degree, b = 5 squareroot 3 C) B = 60 degree, C = 90 degree, b = 5 squareroot 3 D) No solution

Solution

1) a= 42 ; b = 54ft , c = 66 ft

s = (a +b +c)/2 = (42+54+66)/2 = 81 ft

Area = sqrt(s(s-a)(s-b)(s-c) = sqrt(81*39*27*15)

= 1131.1034

= 1131 ft^2 Option D