Two sides of a triangle have lengths 13 m and 15 m The angle

Two sides of a triangle have lengths 13 m and 15 m. The angle between them is increasing at a rate of 2

c^2=a^2+b^2-2abcos(theta) a^2 and b^2 are constants so 2c*dc/dt=390*sin(60)*d(theta)/dt dc/dt=390sin(60)*2/2c dc/dt=337.7/c C=sqrt(a^2+b^2-2abcos(theta) C=sqrt(394-195) C=sqrt(199)=14.11 dc/dt=337.7/14.11=23.94degress=.401 rads So, 0.401 m/min