x2 64 11 Let fx x211x18 a Find the horizontal asymptotes of
Solution
11. f(x) = (x2-64)/(x2-11x +18)=(x+8)(x-8)/(x-8)(x-3)= (x+8)/(x-3)
Horizontal asymptote
Here degree of numerator = degree of denoinator
Therefore, HA, y= numerator\'s leading coefficient/ denominator\'s leading coefficient
y=1/1=1
b. x-3=0
x=3
c. THere is no slant asymptote since degree of numerator and denominator are same .
d. hole is at x-8=0
x=8

