Find the mass of silver chloride obtained by mixing 100 mL o

Find the mass of silver chloride obtained by mixing 10.0 mL of 0.1M AgNO3 and 20.0 mL of 0.05M sodium chloride?

moles of AgNO3 taken = 0.01 L x 0.1 mol / L = 0.001 mol

moles of NaCl taken = 0.02 L x 0.05 mol / L = 0.001 mol

now the balanced reaction is given by

AgNO3 + NaCl --> AgCl + NaNO3

see that AgNO3 and NaCl react in 1 : 1 molar ratio

0.001 mol AgNO3 will react with 0.001 mol NaCl

no limting reagent or nothing is in excess

now

from the balanced reaction

moles of AgCl formed = 0.001 mol AgNO3 x 1 mol AgCl / 1 mol AgNO3

moles of AgCl formed = 0.001 mol

now

mass of AgCl = moles x molar mass

mass of AgCl formed = 0.001 mol x 143.32 g/mol

mass of AgCl formed = 0.14232 g

0.14232 grams of silver chloride is obtained