For 2 if you measure 2000 mL of distilled water 0200 mL of a

For (2), if you measure 20.00 mL of distilled water, 0.200 mL of acetic acid, 1.200 mL of sodium acetate, and 0.500 mL of 1.0 M KI, what will the concentration of KI be in this new solution? Assume that the volumes add (for simplicity). b.

Solution

mmoles of KI = 0.500 x 1 = 0.500

total volume of solution = 20.00 + 0.200 + 1.200 + 0.500

                                     = 21.9 mL

new concentration of KI = mmoles / total volume

                                     = 0.500 / 21.9

concentration of KI = 0.0228 M