Name Section Group value is composed of both your observed a

Name Section Group value is composed of both your observed and expected values for flipping heads and tails. E values are calculated by multiplying the probability So if you flip a coin 10 times, the expected number of heads is of a particular event by the number of observations Eteas Preats One 0.5 10-5 Where Elests is the expected toss, and O is the number of observations or coin tosses. The expected number of tails is also 5. Thus the Chi Square value is calculated as follows if the observed number of heads is 3 and tails is 7 Eneads, Is the expected number of heads, Prheas,is the probability of flipping a heads in single coin The 8/5 = 1.6 Pearson determined that there is a particular probability associated with observing particular Chi Squared values given the number of possible events. However, we don\'t use the number of possible events, we use the degrees of freedom, which are one less than the number of possible events and represent the number of values in a statistic that are free to vary, or the number of statistical tests that can be performed. Armed with a Chi Sqr value and degrees of freedom, we can use Pearson\'s Chi Square Probability Table to determine the probability (P) that the null hypothesis (the deviations from expectation are due to random chance) is true. 1.6, there is approximately a 20% chance e null Referring to the Chi Square Probability Table, with df-1 and that our null hypothesis is true (P o.2). Scientists typically require that PcD.05 in order to reject the nu hypothesis, however this is an arbitrary cutoff. In this particular example, the c2 greater than 3.841 would indicate that there is less than a 5% probability that the null hypothesis is true. sing your data from flipping a single coin 50 times (question 2) and the Chi Square Test, tesf s whether your observed deviation from expectation was due to random chance. In other what is the probability that your coin tosses yielded random results? Provide both your mathematical work, and a plain English interpretation of the test result. 26) Using your data from flipping a single coin 50 times (question 2) and the Chi Square other words,

Solution

Chi-suare test statistics(1.6)<Chi-square cretical value(3.841), so we conclude that accept null hypothess H0