find dydx for yx3x2712Solutionrearrange it taake x inside th
find dy/dx for y=x(3x^2+7)^(1/2)
Solution
rearrange it taake x inside the bracket with sqroot sign
: y = [ 3x4 + 7x2 ] 1/2
y\' = [ 12x3 + 14x ] /2* [ 3x4 + 7x2 ]1/2
y\' = [6x2 + 7]/ [ 3x2 + 7 ]1/2
![find dy/dx for y=x(3x^2+7)^(1/2)Solutionrearrange it taake x inside the bracket with sqroot sign : y = [ 3x4 + 7x2 ] 1/2 y\' = [ 12x3 + 14x ] /2* [ 3x4 + 7x2 ]1 find dy/dx for y=x(3x^2+7)^(1/2)Solutionrearrange it taake x inside the bracket with sqroot sign : y = [ 3x4 + 7x2 ] 1/2 y\' = [ 12x3 + 14x ] /2* [ 3x4 + 7x2 ]1](/WebImages/40/find-dydx-for-yx3x2712solutionrearrange-it-taake-x-inside-th-1122996-1761598056-0.webp)
