man ABO blood groups are controlled by a single gene with th

man ABO blood groups are controlled by a single gene with three alleles I^A, I^B, and i. The three alleles contribute to four blood group phenotypes. In addition to the ABO blood groups, there are two other loci that control blood phenotypes, the MN blood group locus and the Rh factor locus. The MN blood group has two codominant alleles, L^M and L^N. The Rh factor locus also has two alleles, Rh^+ and Rh^- where Rh^+ is dominant. The two phenotypes at the Rh factor locus are Rh^+ and Rh^-. Suppose in a population, the frequency of the ABO allele I^A is 0.36, and the I^B allele frequency is 0.26. In the same population, the frequency of the L^M allele is 0.47, and the frequency of the Rh^+ is 0.62. What is the frequency of the genotype I^AI^A L^ML^N Rh^+ Rh^- if the population is in Hardy-Weinberg equilibrium? Number

Solution

Answer

The frequencies of I^A and I^B are as follows:

I^A = 0.36

I^B = 0.26

So, the allelic frequency of “i” is (1-0.62) = 0.38. Thus, the genotypic frequency of I^AI^A is (0.36)² = 0.129

The allele frequency of LM is as follows:

L^M =0.47

So, the allelic frequency of L^N is (1-0.47) = 0.53. Thus, the genotypic frequency of L^M L^N is (2x0.47x0.53) = 0.49

The allele frequency of Rh⁺ = 0.62

So, the allelic frequency of is Rh^- (1-0.62) = 0.38. Thus, the genotypic frequency of Rh⁺ Rh^- is (2x0.62x0.38) =0.47

Thus, the genotypic frequency of I^A I^A L^M L^N Rh⁺ Rh^- is (0.129x0.49x0.47) = 0.030