Find the first 4 terms of the sequence 3n25n 2 a1 a2 a3
Solution
an=3n2/(5n-2)
a1=3(12)/(5(1)-2) = 3/3=1
a2=3(22)/(5(2)-2)=12/8=4/3
a3=3(32)/(5(3)-2)/27/13
a4=3(42)/(5(4)-2)=48/18=8/3

an=3n2/(5n-2)
a1=3(12)/(5(1)-2) = 3/3=1
a2=3(22)/(5(2)-2)=12/8=4/3
a3=3(32)/(5(3)-2)/27/13
a4=3(42)/(5(4)-2)=48/18=8/3
