Indicate the mean and the standard deviation of the distribu

Indicate the mean and the standard deviation of the distribution of means for each of the following situations.

Solution

Mean and standard deviation for the distribution of mean are

(10/20) = 0.7071

14.) Standard deviation of means are

Mean = Mean	standard deviation = (variance/n)
100	(40/10) = 2
100	(30/10) = 1.7321
100	(20/10) = 1.4142
100	(10/10) = 1
50	(10/10) = 1
100	(40/20) = 1.4142
100	(10/20) = 0.7071