2 A 6x2x1 block made out of AISI 1020 the left end of block

2) A 6”x2”x1” block, made out of AISI 1020 the left end of block is fixed. A downward (bending) load of 10,000 Ib. and a tensile load of 3000 lb. are applied to the right face, as shown below. Using a mesh size of 0.25”. Find

a.Peak (Max value in Probe results for edge, or point) Axial Strain, along the length of block

b.Peak Principal Strain

c.Peak Axial Stress, along the length of block

d.Peak Principal Stress

e.Peak Von-Misses Stress

For both points O and edge A (split A is 1\" in from left side, line O is 1\" in from the bottom)

Solution

Given data

Downward bending load = 10000 lb = 44,482 N

Tensile load = 3000 lb = 13,345 N

E for AISI 1020 = 210 GPa

Area of left end = 2 sq inch = 0.00129032 sqm

a) Axial strain along the length of block = 13,345 / (E x Area of the left end) = 4.93 x 10^-5 m

c) Axial stress along the length of block = E x Axial strain = 10.34 GPa.

d) Max normal stress due to bending = 6 PL / (bh²) = 6 x 44,482 * 0.1524 / (0.0508 x 0.0254 x 0.0254) = 1241 GPa