When adjusted for any changes in delta h and delta S with te

When adjusted for any changes in delta h and delta S with temperature, the standard free energy change delta G at 500K is equal to 9.8x10 4 J/mol. Calculate the equilibrium constant at 500K .

part a answer was 1.32x10^-23= K

part b answer was 1106 K degrees =T

figured them out but this is part C and i dont know how to do it.

Solution

delta G = -R T ln(k)= thus ln(k)=G / -R T =20.571 thus K=1.17*10^(-8)