In the figure below find the following Let e m f1 260 V e m
In the figure below, find the following. (Let e m f1 = 26.0 V, e m f2 = 13.0 V, and R = 19.0 .)
(a) the current in each resistor
 (b) the power delivered to each resistor
Find the potential difference across each resistor in the figure below. (R1 = 5.20 , R2 = 3.80 , R3 = 2.60 , R4 = 1.60 )
| I1 = | A | 
| I2 = | A | 
| I3 = | A | 
Solution
(A) Applying KVL in upper loop:
E1 - 28i1 + 12i2 - E2 = 0
28i1 - 12i2 = 26-13 = 13
28i1 - 12i2 = 13 . .......(i)
 KVL in lower loop:
E2 - 12i2 - RI3 = 0
13 - 12i2 - 19i3 = 0
12i2 + 19i3 = 13 .........(ii)
 Applying KCL ,
i1 + i2 - i3 = 0 ....(iii)
from i, ii and iii,
i1 = 559/1096 = 0.51 A
i2 = 117/1096 = 0.107 A
i3 = 169/274 = 0.617 A
 (B)
for 28 ohm : P1 = i1^2 R1 = 0.51^2 x 28 = 7.28 W
for 12 ohm: P2 = 0.107^2 x 12 = 0.14 W
for R : P3 = 0.617^2 x 19 = 7.23 W

