Homework Soursee2ln5My question is plaease explain what rule I need for thi
e^-2ln5...My question is plaease explain what rule I need for this. I see that the -2 is the exponent to the exponent ln 5 but why and what rule??I see the rule e^lnx=x...but says nothing about a coeffecient in front of the lnx. Where do I look?
Solution
first rule a*logx=logxa
second rule a^(logax)=x
thus your answer will be=e^(-2ln5)=e^(ln5-2)
=5-2
=1/25)
