molecule CHl bp 188 C steam distills at 982C How many of wat

molecule C,Hl bp 188 C) steam distills at 98.2°C. How many of water are requi grams of water per gram of iodobenzene? red to ca tn cary over 1 molecule of iodobenzene How many

Solution

The total vapour pressure of an non-miscible mixture of 2 components is the sum of the partial pressures of each component.

p(t) = p(H2O) + p(Ibenz)

At 98.2 °C the vapour pressure of water is 960 mbar. The atmospheric pressure (at boiling point) is p(t) = 1013 mbar. So we are left with (1013 - 960) mbar = 53 mbar for the partial pressure of I-benzene.

Assuming ideal gas conditions we can set the partial pressures equal to moles or molecules. So we have 960 molecule of water to transport 53 molecules of I-benzene. 18,1 molecule H2O per molecule of iodobenzene.

To convert to gram units, multiply with the correspondent mole masses: 18 g/mol and 204 g/mol.

1.6 g H2O per g I-benzene.