Solve the following equahons over rua 2 Solutionc tan theta1

Solve the following equah\'ons over rua 2.

Solution

c. (tan theta-1)(2sintheta +1)=0

tan theta-1=0 , 2 sin theta +1=0

tan theta=1 , sin theta=-1/2

theta=pi/4, 5pi/4 , theta=7pi/6, 11pi/6

theta=pi/4, 7pi/6, 5pi/4, 11pi/6

d. 2sin²thata=3(1-cos theta)

    2(1-cos²theta)=3(1-cos theta)

2(1+cos theta)=3

cos theta =(3/2)-1 =1/2

theta=pi/3, 5pi/3