Write a function called counts that takes as an integer n th

Write a function called counts() that takes as an integer n, the function counts and returns the number of even digits and the number of odd digits in n. write a program to test your function. For example: For n = 348265, the function returns 4 2 to be printed in main() (shown below as well). Enter an integer number n: 328265 The number of Even digits is 4 The number of odd digits is 2 Process returned 0 execution time: = 4.762 s Press any to continue. Write your function below:

Solution

int counts(int,int);

int main()
{
int nodd,neven,num,digit ;

cout<<\"Enter Integer Number : \';

cin >> num;

int counts(int n1,int n2)
{

nodd = neven =0;

while (num> 0)

{

digit = num % 10; /* separate LS digit from number */

if (digit % 2 == 1)

nodd++;

else neven++;

num /= 10; /* remove LS digit from num */

}

return counts;

}