If the probability for a vehicle to pass inspection is 39 as

If the probability for a vehicle to pass inspection is 39%, assuming that vehicle passing rates are independent, If there were 10 cars,

What is the probability that 2 or fewer would pass?

Round final answer to 3 decimal places.

Solution

If the probability for a vehicle to pass inspection is 39%, assuming that vehicle passing rates are independent, If there were 10 cars,

What is the probability that 2 or fewer would pass?

n=10

p=0.39

Binomial distribution used.

P(X=x) = (nCx) px (1-p)n-x

P( x 2)= P( x=0)+P( x=1)+P( x=2)

= 0.0071+ 0.0456+ 0.1312

=0.1839

If the probability for a vehicle to pass inspection is 39%, assuming that vehicle passing rates are independent, If there were 10 cars, What is the probability

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