A torus is generated by rotating the circle x 2 y 6 2 9

A torus is generated by rotating the circle x^ 2 + ( y - 6 ) ^2 = 9 about the x-axis. Find the volume enclosed by the torus.

Note that x = ± v[9 - (y - 6)²] and y is in [3, 9] (by setting x = 0 in the torus\' equation). So, the volume equals ?(y = 3 to 9) 2py v[9 - (y - 6)²]- (-v[9 - (y - 6)²]])} dy = ?(y = 3 to 9) 4pyv[9 - (y - 6)²] dy