What is the mass of 6022 x 1023 compounds of NH4AISO4212H2O

What is the mass of 6.022 x 1023 compounds of NH4AI(SO4)2·12H2O?

Solution

According to avogadro\'s law 1 mole of subtance contain 6.022 X 10²³ molecule

therefore 6.022 X 10²³ molecule of compound NH₄Al(SO₄)₂.12H₂O   = 1 mole of NH₄Al(SO₄)₂.12H₂O

molar mass of NH₄Al(SO₄)₂.12H₂O = 453.3102 g/mol

1 mole of NH₄Al(SO₄)₂.12H₂O = 453.3102 gm

therefore mass of 6.022 X 10²³ molecule of compound NH₄Al(SO₄)₂.12H₂O = 453.3102 gm