5 Squareroot y Squareroot x5 Squareroot y 4 Squareroot x 2

(5 Squareroot y + Squareroot x)(5 Squareroot y - 4 Squareroot x) (2 Squareroot 2y - 3 Squareroot 3x)(4 Squareroot 2y - Squareroot 3x) divide the radicals. Rationalize the denominators and simplify if possible. 2/Squareroot 5y y/Squareroot 15

Solution

3) We have (5y+x)(5y-4x)=(5y)(5y)–(5y)(4x)+(x)(5y)–(x)(4x) = 25y -20(xy) +5(xy) -4x = 25y -15(xy) -4x.

4) We have [2(2y)-3(3x)][4(2y)-(3x)]=[2(2y)][4(2y)]–[3(3x)][4(2y)]–[2(2y)][(3x)]+[ 3(3x)][(3x)] = 8*2y - 12(6xy) -2(6xy) + 3*3x = 16y –(146)(xy)+9x.

5) We have 2/(5y) = 2(5y) / [(5y) (5y)] = 2(5y)/5y

6) We have y/(15) = y(15)/[(15) ][[(15)] = y(15)/15